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Intermediate Algebra
Conic Sections (online only)

1
Summary

Problem  1

Find \(x\) so that \((x,2)\) is \(2\sqrt{5}\) units for \((-1,4)\).

Choose instructor to watch:
Mr. Neufeld cc
Mr. Neufeld
Sirena cc
Sirena
Problem  2

Give the equation of the circle with center at \((-2,4)\) and radius \(3\).

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Mr. Neufeld cc
Mr. Neufeld
Sirena cc
Sirena
Problem  3

Give the equation of the circle with center at the origin that contains the point \((-3,-4)\).

Choose instructor to watch:
Mr. Neufeld cc
Mr. Neufeld
Sirena cc
Sirena
Problem  4

Find the center and radius of the circle: \(x^2+y^2-10x+6y=5\)

Choose instructor to watch:
Mr. Neufeld cc
Mr. Neufeld
Sirena cc
Sirena
Problem  5

Graph each of the following: \(4x^2-y^2=16\)

Choose instructor to watch:
Mr. Neufeld cc
Mr. Neufeld
Sirena cc
Sirena
Problem  6

Graph each of the following:
\(\displaystyle\frac{x^2}{25}+\displaystyle\frac{y^2}{4}=1\)

Choose instructor to watch:
Mr. Neufeld cc
Mr. Neufeld
Sirena cc
Sirena
Problem  7

Graph each of the following:
\((x+2)^2+(y+1)^2\leq 9\)

Choose instructor to watch:
Mr. Neufeld cc
Mr. Neufeld
Sirena cc
Sirena
Problem  8

Graph each of the following:
\(9x^2+4y^2-72x-16y+124=0\)

Choose instructor to watch:
Mr. Neufeld cc
Mr. Neufeld
Sirena cc
Sirena
Problem  9

Solve the following system:

\[\begin{aligned} x^2+y^2 &= 25\\ 2x+y &= 5\end{aligned}\]

Choose instructor to watch:
Mr. Neufeld cc
Mr. Neufeld
Sirena cc
Sirena
Problem  10

Solve the following system:

\[\begin{aligned} x^2+y^2 &= 16\\ y&=x^2-4\end{aligned}\]

Choose instructor to watch:
Mr. Neufeld cc
Mr. Neufeld
Sirena cc
Sirena

2
Circles

Problem  1
practice icon

Find the distance between \((3,5)\) and \((2,-1)\).

Choose instructor to watch:
Betsy cc
Betsy
Gordon cc
Gordon
Gordon espanol spanish
Gordon
Problem  2
practice icon

Find \(x\) if the distance from \((x,5)\) to \((3,4)\) is \(\sqrt{2}\).

Choose instructor to watch:
Stefanie cc
Stefanie
Preston cc
Preston
Mr. Martinez espanol spanish
Mr. Martinez
Problem  3
practice icon

Find the equation of the circle with center at \((-3,2)\) having a radius of \(5\).

Choose instructor to watch:
Betsy cc
Betsy
Gordon cc
Gordon
Gordon espanol spanish
Gordon
Problem  4
practice icon

Give the equation of the circle with radius \(3\) whose center is at the origin.

Choose instructor to watch:
Stefanie cc
Stefanie
Preston cc
Preston
Mr. Martinez espanol spanish
Mr. Martinez
Problem  5
practice icon

If \((x-1)^2 +(y+3)^2=4\) find the center, radius, and graph the circle.

Choose instructor to watch:
Mr. McKeague cc
Mr. McKeague
Betsy cc
Betsy
Gordon cc
Gordon
Gordon espanol spanish
Gordon
Problem  6
practice icon

Sketch \(x^2+y^2=9\)

Choose instructor to watch:
Stefanie cc
Stefanie
Preston cc
Preston
Mr. Martinez cc espanol spanish
Mr. Martinez
Problem  7
practice icon

Sketch \(x^2+y^2+6x-4y-12=0\)

Choose instructor to watch:
Betsy cc
Betsy
Gordon cc
Gordon
Gordon espanol spanish
Gordon
Mini Lecture

Mini Lecture

  1. Find the distance between \((3,-5)\) and \((-2,1)\).

  2. Find \(x\) so the distance between \((x,2)\) and \((1,5)\) is \(\sqrt{13}\).

  3. Find the equation of the circle with its center at \((3,-2)\) and radius \(3\).

Graph the following

4. \(x^2+y^2=4\) \(\qquad\) 5. \(x^2+y^2-6y=7\)
Choose instructor to watch:
Mr. McKeague cc
Mr. McKeague

3
Parabolas

Problem  1
practice icon

Graph \(y=2(x-1)^2-3\)

Choose instructor to watch:
Stephanie cc
Stephanie
Joshua
Joshua
Cynthia espanol spanish
Cynthia
Problem  2
practice icon

Graph \(y=x^2+4x+7\)

Choose instructor to watch:
Stephanie cc
Stephanie
Joshua
Joshua
Cynthia espanol spanish
Cynthia
Problem  3
practice icon

Graph \(y=-2x^2+8x+3\)

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Stephanie cc
Stephanie
Joshua
Joshua
Cynthia espanol spanish
Cynthia
Problem  4
practice icon

Graph \(x=-2(y+3)^2+4\)

Choose instructor to watch:
Stephanie cc
Stephanie
Joshua
Joshua
Cynthia espanol spanish
Cynthia
Problem  5
practice icon

Graph \(x=y^2-4y-2\)

Choose instructor to watch:
Joshua
Joshua
Julieta cc
Julieta
Cynthia espanol spanish
Cynthia
Problem  6
practice icon

Graph \(x=3y^2-6y+1\)

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Stephanie cc
Stephanie
Joshua
Joshua
Cynthia espanol spanish
Cynthia
Problem  7
practice icon

A parabola has a vertex of \((3, -2)\) and \(x\)-intercepts of \(0\) and \(6\). Find its equation.

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Stephanie cc
Stephanie
Joshua
Joshua
Cynthia espanol spanish
Cynthia
Problem  8
practice icon

A parabola has a vertex of\((-4, 1)\) and \(y\)-intercepts of \(-7\) and \(9\). Find its equation.

Choose instructor to watch:
Stephanie cc
Stephanie
Joshua
Joshua
Cynthia espanol spanish
Cynthia
Mini Lecture

Mini Lecture
Graph:

  1. \(y=-x^2-2x+3\)

  2. \(y=-2x^2+6x-5\)

Choose instructor to watch:
Mr. McKeague cc
Mr. McKeague

4
Ellipses

Problem  1
practice icon

Sketch the graph of \(\dfrac{x^2}{9}+\dfrac{y^2}{36}=1\)

Choose instructor to watch:
Molly S. cc
Molly S.
Logan
Logan
Cynthia espanol spanish
Cynthia
Problem  2
practice icon

Sketch \(4x^2+9y^2=36\)

Choose instructor to watch:
Molly S. cc
Molly S.
Stefanie cc
Stefanie
Gordon cc
Gordon
Gordon espanol spanish
Gordon
Problem  3
practice icon

Graph \(x^2+9y^2+4x-54y+76=0\)

Choose instructor to watch:
Stefanie cc
Stefanie
Gordon cc
Gordon
Gordon espanol spanish
Gordon
Mini Lecture

Mini Lecture
Graph the following ellipses.

  1. \(\displaystyle\frac{x^2}{16}+\displaystyle\frac{y^2}{9}=1\)

  2. \(x^2+8y^2=16\)

Graph the following hyperbolas.

  1. \(\displaystyle\frac{x^2}{16}-\displaystyle\frac{y^2}{9}=1\)

  2. \(x^2-4y^2=4\)

Choose instructor to watch:
Mr. McKeague cc
Mr. McKeague

5
Hyperbolas

Problem  1
practice icon

Graph \(\displaystyle\frac{y^2}{9}-\displaystyle\frac{x^2}{16}=1\)

Choose instructor to watch:
Betsy cc
Betsy
Preston cc
Preston
Mr. Martinez espanol spanish
Mr. Martinez
Problem  2
practice icon

Graph the equation \(64x^2-16y^2=64\)

Choose instructor to watch:
Stephanie cc
Stephanie
Logan
Logan
Cynthia espanol spanish
Cynthia
Problem  3
practice icon

Graph \(4x^2-y^2+4y-20=0\)

Choose instructor to watch:
Betsy cc
Betsy
Preston cc
Preston
Mr. Martinez espanol spanish
Mr. Martinez
Mini Lecture

Mini Lecture
Graph the following ellipses.

  1. \(\displaystyle\frac{x^2}{16}+\displaystyle\frac{y^2}{9}=1\)

  2. \(x^2+8y^2=16\)

Graph the following hyperbolas.

  1. \(\displaystyle\frac{x^2}{16}-\displaystyle\frac{y^2}{9}=1\)

  2. \(x^2-4y^2=4\)

Choose instructor to watch:
Mr. McKeague cc
Mr. McKeague

6
Nonlinear Systems of Equations and Inequalities

Problem  1

Graph \(x^2+y^2<16\)

Choose instructor to watch:
Stefanie cc
Stefanie
Gordon cc
Gordon
Gordon espanol spanish
Gordon
Problem  2

Graph \(y\leq x^2-2\)

Choose instructor to watch:
Betsy cc
Betsy
Preston cc
Preston
Mr. Martinez espanol spanish
Mr. Martinez
Problem  3

Graph \(4y^2-9x^2<36\)

Choose instructor to watch:
Stefanie cc
Stefanie
Gordon cc
Gordon
Gordon espanol spanish
Gordon
Problem  4
practice icon

Solve

\[\begin{aligned} x^2+y^2&=4\\ x-2y&=4\end{aligned}\]

Choose instructor to watch:
Betsy cc
Betsy
Preston cc
Preston
Mr. Martinez espanol spanish
Mr. Martinez
Problem  5
practice icon

Solve

\[\begin{aligned} 16x^2-4y^2&=64\\ x^2+y^2&=9\end{aligned}\]

Choose instructor to watch:
Stefanie cc
Stefanie
Gordon cc
Gordon
Gordon espanol spanish
Gordon
Problem  6
practice icon

Solve

\[\begin{aligned} x^2-2y&=2\\ y&=x^2-3\end{aligned}\]

Choose instructor to watch:
Mr. McKeague
Mr. McKeague
Betsy cc
Betsy
Preston cc
Preston
Mr. Martinez espanol spanish
Mr. Martinez
Problem  7
practice icon

The sum of the squares of two numbers is \(34\). The difference of their squares is \(16\). Find the two numbers.

Choose instructor to watch:
Stefanie cc
Stefanie
Gordon cc
Gordon
Gordon espanol spanish
Gordon
Problem  8

Graph the solution set for the system

\[\begin{aligned} x^2+y^2 &\leq 9\\ \frac{x^2}{4}+\frac{y^2}{25} &\geq 1\end{aligned}\]

Choose instructor to watch:
Betsy cc
Betsy
Preston cc
Preston
Mr. Martinez espanol spanish
Mr. Martinez
Mini Lecture

Mini Lecture
Graph the following.

  1. \((x-2)^2+(y+3)^2<16\)

  2. \[\begin{aligned} x^2+y^2&<9\\ y&\geq x^2-1\end{aligned}\]

  3. Solve the system

    \[\begin{aligned} x^2+y^2&=9\\ 2x+y&=3\end{aligned}\]

Choose instructor to watch:
Mr. McKeague cc
Mr. McKeague